# Solving Math Problems With Solutions

Then the second cow produced $(8100 - x)$ litres of milk that year.The second year, each cow produced the same amount of milk as they did the first year plus the increase of \%$or \%$.So 00 \frac\cdot x \frac \cdot (8100 - x) = 9100$Therefore 00 \fracx \frac(8100 - x) = 9100$$\fracx = 190$$x = 3800$Therefore, the cows produced 38 litres of milk the first year, and 70$and 30$ litres of milk the second year, respectively.

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Because of a closed road he had to change his route, making the trip 28 km longer. Solution: From the statement of the problem we don't know if the 15 min stop in town C was planned or it was unexpected. If the driver could use the initial route, it would take him $x - \frac = x - \frac$ hours to drive from C to B.

Solution: Let $x$ be the number of kilograms he sold in the morning. Problem 2 Mary, Peter, and Lucy were picking chestnuts. Solution: Let $x$ be the total number of pages in the book, then she finished $\frac\cdot x$ pages.

Then she has $x-\frac\cdot x=\frac\cdot x$ pages left.

How many hectares a day would one tractor plough then?

Solution: If each of $tractors ploughed 0$ hectares a day and they finished the work in $days, then the whole field is: 0\cdot 6 \cdot 4 = 720 \cdot 4 = 2880$ hectares.

## Comments Solving Math Problems With Solutions

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